RE: A Challenge

[Garrett Wollman <wollman>]

<<On Sun, 27 Jul 1997 19:32:53 +0000, Dan Strassberg <dan.strassberg@worldnet.att.net> said:

> Well, that makes my 75% number a bit low--but AMs are allowed to modulate
> 125% on positive peaks. So peak power out for a 50 kW AM is 2.25^2*50 kW =
> over 250 kW. If the modulation is a symmetrical squarewave, the average
> power out is 125 kW. 125/.85 = 147 kw. That would be the input power. I had

Your calculation made me curious enough to pull out the glossy again.
Here's what they claim:

Power consumption: 59 kW or less (typical) at 50 kW, 0% modulation, 88
kW or less (typical) at 50 kW, 100% tone modulation.

Overall efficiency: 93% or better.  Typically 85% at 50 kW.

Positive Peak Capability: +145% at 50 kW, +135% at 55 kW, 125% at 60
kW (pgm mod).

Weight: Unpacked: 3770 lbs. (1710 kg. [sic]); Packed: 4670 lbs. (2123
kg. [sic])

I understand they also make similar products for sale into the world
market at powers of up to 2 MW.  (Probably in quantity five...)

- -GAWollman

- --
Garrett A. Wollman   | O Siem / We are all family / O Siem / We're all the same
wollman@lcs.mit.edu  | O Siem / The fires of freedom 
Opinions not those of| Dance in the burning flame
MIT, LCS, CRS, or NSA|                     - Susan Aglukark and Chad Irschick

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